MS Chauhan Aldol & Cannizzaro reactions Solutions (Chapter 8)
MS Chauhan Organic Chemistry Solutions Chapter 8 will introduce you to a few basic and advanced techniques, which will let you define the various ways of Aldol and Cannizzaro Reaction. The problems of this chapter are completely based on the mechanism of aldol and Cannizzaro reaction. It is one of the interesting chapters featured in the MS Chauhan Organic Chemistry Solutions for Class 11 and 12.
These solutions are a highly beneficial contribution to the success of not only your academic exams but also to prepare for the entrance exams like IIT JEE and NEET. The important topics of Chapter 8 – Aldol & Cannizzaro Reactions include the aldol reaction, Cannizzaro reaction, mechanism of aldol reaction, and mechanism of Cannizzaro reaction. Referring to MS Chauhan Organic Chemistry Solutions for Aldol and Cannizzaro Reaction will help you make sure that you do not miss any important questions during the preparation of your exams.
The chapter of Organic Chemistry MS Chauhan Solutions for Class 12 contains 2 main levels of exercises with a total of 52 questions. There are different types of questions available in both the exercises for your reference which in turn will help to prepare for the competitive exams well. Solving difficult problems in Chapter 8 with the help of these solutions will help you initiate new ways of solving the questions with different techniques. You can follow the solutions provided by the expert Chemistry teachers at Instasolv for your better understanding of the concepts.
Important Topics for MS Chauhan Organic Chemistry Solutions Chapter 8 Aldol & Cannizzaro Reactions
A chemical reaction that includes the induced base disproportionation of two particles of a non-enolizable aldehyde to produce a carboxylic acid and main alcohol is known as Cannizzaro reaction.
Mechanism of Cannizzaro Reaction
Cannizzaro Reaction Mechanism specifies the procedure to obtain one molecule of alcohol and one molecule of carboxylic acid from two molecules of a provided aldehyde. When the experiment was performed, benzyl alcohol and potassium benzoate were obtained from benzaldehyde. The reaction is performed by a nucleophilic acyl replacement on an aldehyde where the parting group attacks another aldehyde. Tetrahedral transitional results from the outbreak of hydroxide on a carbonyl. This tetrahedral intermediate downfalls, thus improving the carbonyl and transporting a hydride that outbreaks another colony.
Now, a proton is replaced by acid and alkoxide ions. When a base of great concentration is presented, the aldehyde generates an anion which has a charge of 2. From this, a hydride ion is transported to a second molecule of the aldehyde, creating carboxylate and alkoxide ions. The alkoxide ion also achieves a proton from the solvent for the reaction.
Step 1: A nucleophile including a hydroxide ion is used to outbreak the carbonyl group of the specified aldehyde, producing a disproportionation reaction and offering rise to an anion transporting 2 negative charges.
Step 2: This subsequent intermediate can now purpose as a hydride reducing agent. Due to its unstable nature, the intermediate discharges a hydride anion. This hydride anion continues to outbreak another aldehyde molecule. At this time, the doubly charged anion is transformed into a carboxylate anion and the aldehyde is transformed into an alkoxide anion.
Step 3: This is the last step of the mechanism, water provides a proton to the alkoxide anion which offers rise to the last alcohol product. The reaction can continue as the alkoxide is more basic in nature than water. At this time, the carboxylate ion offers rise to the last carboxylic acid product when an acid examination is used in the process.
Aldol condensation usually happens in aldehydes consisting of α-hydrogen with a dilute base to provide β-hydroxy aldehydes known as aldols. This reaction is generally called aldol condensation. If the condensation reaction happens between two diverse carbonyl compounds it is known as crossed aldol condensation.
Aldol Condensation refers to an organic reaction in which enolate ion available reacts further with a carbonyl compound to generate β-hydroxy ketone or β-hydroxy aldehyde, tracked by dehydration to provide a conjugated enone. Aldol Condensation plays an important role in organic synthesis, generating a way to generate carbon-carbon bonds.
Mechanism of Aldol Condensation
Step 1: When considered in reverse order, the hydroxide ion available in the reaction deprotonates the aldehyde.
Step 2: In this step of the mechanism, enolate ion 1 adds further to the unreacted aldehyde.
Step 3: Here, alkoxide ion 2 is protonated by water.
Step 4: This mechanism step contains a small amount of aldol which is transformed into enolate ion (4) by hydroxide ion.
Step 5: Here, Enolate Ion (4) misplaces a hydroxide ion.
Exercise-wise Discussion for MS Chauhan Organic Chemistry Solutions Chapter 8 Aldol & Cannizzaro Reactions
In this MS Chauhan Organic Chemistry Solutions for Chapter 8 – Aldol and Cannizzaro Reaction, you will find two main levels of exercises with 52 questions in total. These questions are based on all the important topics of the chapter. The different types of questions include objective type questions, match the following, subjective questions, and very short answer type questions. The description of both the levels are listed below:
Level 1: In this level of MS Chauhan Aldol and Cannizzaro Reaction Solutions, there are a total of 44 questions based on the mechanism of aldol and Cannizzaro reaction. These are objective type questions which are considered important from a competitive exam point of view. Preparing these questions will help you score good marks in the competitive exams like JEE and NEET.
Level 2: This level of MS Chauhan Chapter 8 Solutions consists of a total of 8 questions. There are two different types of questions available at this level including very short answer type questions and subjective problems. You will also find a few matches the following type questions, where you have to match the option in column one to the correct options in column two. Practice well to make your concepts stronger.
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