Question

( f(x)=frac{log _{2}(x+3)}{x^{2}+3 x+2} )
log fundion canhot take angument ( leq 0 )
( therefore x+3>0 quad ) se ( x>-3 )
Also denominator canmot me equal to 0
( x^{2}+3 x+2 eq 0 )
( [x+1)(x+2) eq 0 )
( therefore x eq div 1,-2 )
( therefore ) Demain ( =(-3, infty) sim{-1,-2} )
( operatorname{Ans} rightarrow(D) )

# (0) 1 1 (4) R 19. The domain of f(x) = log2 (x+3) is x + 3x+2° (1) R-4-1, -23 (2) (-2, too) (3) R-{-1, 2, - 3} (4) (-3, +00)--1-2)

Solution