Question

(0) 1 1 (4) R 19. The domain of f(x) = log2 (x+3) is x + 3x+2° (1) R-4-1, -23 (2) (-2, too) (3) R-{-1, 2, - 3} (4) (-3, +00)--1-2)

JEE/Engineering Exams

Maths

Solution

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( f(x)=frac{log _{2}(x+3)}{x^{2}+3 x+2} ) log fundion canhot take angument ( leq 0 ) ( therefore x+3>0 quad ) se ( x>-3 ) Also denominator canmot me equal to 0 ( x^{2}+3 x+2 eq 0 ) ( [x+1)(x+2) eq 0 ) ( therefore x eq div 1,-2 ) ( therefore ) Demain ( =(-3, infty) sim{-1,-2} ) ( operatorname{Ans} rightarrow(D) )