Question
- 0.1 x 0.1x0.1 + 0.02 x 0.02x0.02 0.2x0.2x0.2 + 0.04 X 0.04 x 0.04 का मान है। (I) 0.0125 (2) 0.125 (3) 0.25 (4) 0.5 ।
Solution 61. (2) माना 0.1 = 4 :: 0.2 = 2a
एवं 0.02 = b :: 0.04 = 2b
a + b3
.:. व्यंजक = 843+8b3
-100
= 0.125
80s
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expansion of the wire is a,- 0.1 x 0.1x0.1 + 0.02 x 0.02x0.02
0.2x0.2x0.2 + 0.04 X 0.04 x 0.04
का मान है।
(I) 0.0125 (2) 0.125
(3) 0.25
(4) 0.5 ।
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