Question

61. (2) माना ( 0.1=a therefore 0.2=2 a )
एवं ( 0.02=b therefore 0.04=2 b )
( therefore ) व्यंजक ( =frac{a^{3}+b^{3}}{8 a^{3}+8 b^{3}} )
( =frac{a^{3}+b^{3}}{8left(a^{3}+b^{3}right)}=frac{1}{8}=0.125 )

# - 0.1 x 0.1x0.1 + 0.02 x 0.02x0.02 0.2x0.2x0.2 + 0.04 X 0.04 x 0.04 का मान है। (I) 0.0125 (2) 0.125 (3) 0.25 (4) 0.5 ।

Solution