Question

( =2.5 x )
( k )
( frac{sqrt{8}}{60} c_{4}=2 times 10 )
( sqrt{3} times frac{1}{4} )
( mathcal{V} )
( c^{2}=a^{2}+b^{2}-2 a b cos c )
( begin{aligned}=& 64+16-64left(frac{1}{2}right) =& 48 C=sqrt{48}=4 sqrt{3} frac{4 sqrt{3}}{sin (60)}=frac{8}{8 i n(13)} end{aligned} )
7) ( sin B=frac{8 x sqrt{3} / 2}{4 sqrt{3}}=1 quad therefore quad B=90^{circ} )

# - (0) In the triangle ABC, a=4, b=8, c=60º find angle B. त्रिभुज ABC में कोण B का मान कीजिए जहां a=4, b=8, c=60°

Solution