Question

( 8 tan ^{2} frac{x}{2}=1+frac{1}{cos x} )
( operatorname{stan}^{2} frac{x}{2}=1+frac{1+tan ^{2} x / 2}{1-tan ^{2} x / 2} )
( tan x / 2=pm frac{1}{sqrt{2}} cdot 4 t(1-t)=1 )
( sin ^{2} frac{x}{2}=frac{2}{1-tan ^{2} x / 2} )
( cos frac{x}{2}=pm frac{sqrt{2}}{3} cdot begin{array}{c}4 t-4 t^{2}=1 4 t^{2}-4 t+1=0 (2 t-1)^{2}=0end{array} )
( therefore ) None of these ( t=1 / 2 )

# -=1 + sec x is: The general solution of 8 tan2 x = 2nn + -- x = 2nn † cos None of these Number of

Solution