Question

decay const relationship is giren by
[
begin{array}{l}
T_{12}=frac{0.693}{lambda}
therefore lambda=frac{0.693}{T_{1 / 2}}=frac{0.645}{1386 times 1000}
=5 times 10^{-4} mathrm{sec}^{-1}
end{array}
]

# ( 10 sition 34. tion The half life for radioactive sample is 1386 s then its decay constant (a) is (1) 5 x 10-2 sec-1 (2) 5 x 10-3 sec-1 (3) 5 x 10 sec1 (4) 5 x 10-5 sec-1

Solution