Question

(ביני2־יי (וסיבי (ש) 15. (3) (-/3 + -2) (2 /3 - i)

JEE/Engineering Exams

Maths

Solution

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( sqrt{-2}=sqrt{2} i ) ( therefore quad(-sqrt{3}+sqrt{2} i)(2 sqrt{3}-i) ) ( =-2|3|+2 sqrt{6} i+sqrt{3} i eq sqrt{2} ) ( =(sqrt{2}-b)+i(2 sqrt{b}+sqrt{3}) )