Question

Oxichnion state in Tyitrogen in ( n 1,44 quad i & quad(-2) )
[
2(-2)+4(+1)=0
]
therefore 2 M moikes it -4 . Since,
-they lose 16 nole efectrongle hence andrae is
In ( N_{2} H_{4} ) Nitrogen hax - 2 oxiol ( ^{n} ) state
SO, 1 role has ( 2 x(-2)=4 )
for 2 ronelett is -8 for overall Nitrogen for 2 moless
Now 16 moles ( e^{circ} ) are removed for 2
molecules
( (-8+16)=+8 )
In nlew moleuites oxidation state ( sqrt{8} ) exch nitrogen is ( frac{18}{4}=+2 ) Diniofed by 4 because ureraln
( 2 sin theta beta )
and 2 nitsogen atomy fur rovele eule. option ( (0,) ) is correction

# .2 mole of N,H, loses 16 mole of electron is being converted to a new compound X. Assuming that all of the N appears in the new compound. What is the oxidation state of 'N' in X ? (a) -1 (b) -2 (c) +2 (d) +4

Solution