Question

.2 mole of N,H, loses 16 mole of electron is being converted to a new compound X. Assuming that all of the N appears in the new compound. What is the oxidation state of 'N' in X ? (a) -1 (b) -2 (c) +2 (d) +4

JEE/Engineering Exams

Chemistry

Solution

4.0 (1 ratings)

Oxichnion state in Tyitrogen in ( n 1,44 quad i & quad(-2) ) [ 2(-2)+4(+1)=0 ] therefore 2 M moikes it -4 . Since, -they lose 16 nole efectrongle hence andrae is In ( N_{2} H_{4} ) Nitrogen hax - 2 oxiol ( ^{n} ) state SO, 1 role has ( 2 x(-2)=4 ) for 2 ronelett is -8 for overall Nitrogen for 2 moless Now 16 moles ( e^{circ} ) are removed for 2 molecules ( (-8+16)=+8 ) In nlew moleuites oxidation state ( sqrt{8} ) exch nitrogen is ( frac{18}{4}=+2 ) Diniofed by 4 because ureraln ( 2 sin theta beta ) and 2 nitsogen atomy fur rovele eule. option ( (0,) ) is correction