*=-2, y = -3, and z = 5 equation Find the zeros of 9x) - 27x2 + 26x - 8, given that double the other * - 27x2 + 26x - 8, given that one of the zeros of this equalis

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let a be a root, then ( 2 a ) is also a root. ( 9 a^{3}-27 a^{2}+26 a-8=9left(8 a^{3}right)-27left(4 a^{2}right) ) ( 63 a^{3}-81 a^{2}+26 a=0 ) a ( left(63 a^{2}-81 a-26right)=0 ) eifhr ( a=0 ) or ( 63 a^{2}-81 a-26=0 ) ( 2 a=frac{84}{126} ) or ( frac{78}{126} )

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