(20) The minimum value of 12-1+2–2 + 2-3 + 2–4 +2–5 is 1) 3 2) 5 37 146

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( Rightarrow|z-1|+|z-2|+|z-3|+|z-4|+|z-5| ) ( therefore ) As all functions are modulus ( therefore ) we choose middle value ( 6 cdot 3=z ) ( therefore(3-i|+| 3-2|+| 3-3)+(3-4)+|3-5| ) ( =6 mid quad(4) 6 )

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