| ) । (233-7 वे 263 र
Question
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| ) । (233-7 वे 263 र

JEE/Engineering Exams
Maths
Solution
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( (Q) quad 6 x^{2}-7 x-3=0 ) ( 6 x^{2}-7 x-3=0 quad frac{24}{7^{2}} ) By quadratuc formula: - ( x=frac{-b pm sqrt{b^{2}-4 a c}}{2 a} ) ( x=frac{7 pm sqrt{49+72}}{12}=frac{7 pm 11}{12} ) ( x=frac{7+11}{12}=frac{18}{1.2}=sqrt{frac{3}{2}} ) ( -pi quad n=frac{7-11}{12}=frac{-4}{12}=-frac{1}{3} )
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