Question

(3) 0.1 (4) 0.2 19. The amount of HCI formed when 8 g of hydrogen gas (H2) reacts with 142 g of chlorine gas (Cl2) is (Atomic mass of Cl = 35.5 u) H2 + Cl2 → 2HCI (1) 739 07146 9 (3) 107 g (4) 92 g ant

JEE/Engineering Exams

Chemistry

Solution

202

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( mathrm{H}_{2}+mathrm{U}_{2} rightarrow 2 mathrm{H} mathrm{Cl} ) ( 8 y quad 142 g quad rightarrow ) anno ( u^{prime} downarrow ) 4 mol 2 mol cle is tomiting reagent So, ( 4 mathrm{HC} rightarrow 4[355+1] ) ( Rightarrow 142+4 g ) ( =1469 ) An