Question

( frac{17}{3}+left[frac{left.3left(2 x-frac{5}{3}right)right]}{2}=frac{1}{6}right. )
( frac{34}{3}+left[3left(2 x-frac{5}{3}right)right]=frac{1}{3}{ ) mutiplying
( frac{33}{3}+left[3left(2 x-frac{5}{3}right)right]=0 )
( 11+[6 x-5]=0 )
( 11+6 x-5=0 )
( 6+6 x=0 Rightarrow-6 x=-6 )
( Rightarrow[x=-1]_{4} )

# (3) 0.100 17. If17/3+ [3(2x-5/3)]/2 =1/6, then what is the value of x ? (2) 3 (3) -3 (1)1 (4) -1

Solution