(3) 0 (4) 3 Let z be the set of all integers and A = {(a, b): a2 + 3b2 = 28, a, b e Z) B = {(a, b): a > b, a, b e 7), then n( A (1) 1 (3) 3 B) is equal to (2) 6 (4) 8

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( f circ 2 quad A ) ( a^{2}+3 b^{2}=28 ) ( 6=3, a=1 ) ( v=-3, quad 9=-1 ) ( 6=2,9=4 ) ( b=-2,1-4 ) Gut as givin i asb ( 6=-3,9=-1 ) ( i=2, a=4 ) ( b=1,9=5 ) If elecelezex su ( n(x+3)=3 )

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