(3) G2 Hzz 0 11 (4) CgH_03 10. How ...
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(3) G2 Hzz 0 11 (4) CgH_03 10. How many moles of magnesium phosphate, Mg, (PO), will contain 0.25 mole of oxygen atoms? (1) 3.125 * 10-2 (2) 1.25 × 10-2 (3) 2.5 × 10-2 (4) 0.125

JEE/Engineering Exams
Chemistry
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1 mole of Mg3(PO4)2 contains 8 moles of Oxygen Then, 8 moles of oxygen is contained by 1 mole of ( mathrm{Mg} 3(mathrm{PO} 4) 2 ) 0.25 moles of oxygen is contained by [ ( left.left(0.25^{*} 1right) div 8right]=25 div 800=0.03125 ) moles of ( mathrm{Mg} 3(mathrm{PO} 4) 2 . ) So, your answer is 0.03125 moles
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