Question

Download App for Answer

# [34). PT is a tangent and PAB is a secant of a circle. If PB = 9 cm, PT = 6 cm, then AB will be : (a) 6 cm (b) 4 cm (c) 5 cm O (d) 4.5 cm 100

JEE/Engineering Exams

Maths

Solution

Share

106

4.0 (1 ratings)

106

4.0 (1 ratings)

Rate Solution

Share

Relevant Questions

OABC is a parallelogram. If OA = ā and OC = C, find the vector equation of the stue
Mar. '15 (TS); M...

JEE/Engineering Exams

Maths

The centroid of an equilateral triangle is (0,0) and the length of the altitude is 6. The equation o...

JEE/Engineering Exams

Maths

For what Values of K the Expression Kast (k+1)22)
will be a pesuthet de mare far m
mace of a theay p...

JEE/Engineering Exams

Maths

If the value of sin π/14 sin 3π/14 sin 5π/14 sin 7π/14 sin 9π/14 sin 11π/14 sin 13π/14 is equal to k...

JEE/Engineering Exams

Maths

(4) x cosx + sinx
15. Find slope of curve 3y - 2x - 5 = 0.
NIw wina

JEE/Engineering Exams

Maths

>

Recent Questions