Question

[
begin{array}{l}
quad x=10 times 10^{-2} sin 30^{circ}
E=frac{Delta V}{Delta n}
E=frac{40-20}{10 times 10^{-2} sin 30^{circ}}
E=frac{tan 20}{10^{circ}+frac{1}{2}}
E=400 N / C
end{array}
]
Bption 4 is Correct

# (+) 35 If the given figure shows equipe the magnitude of electric field is shows equipotential surfaces, then 80 V 60 V 40 V 20 V 30° -10 cm (1) 50 N/C (3) 200 N/C (2) 100 N/C (4) 400 N/C

Solution