Question

( gamma alpha frac{n^{2}}{2} )
( frac{gamma_{H}}{sigma_{H e}+frac{n_{H}^{2}}{2 mu}} times frac{2_{H e}+}{n_{H e}} )
( gamma_{H e}+=frac{D cdot 53 times 1 times(2)^{8}}{(1)^{2} times x}=1.06 mathrm{A} )

# (4)1:1:1 10. The radius of the first orbit of hydrogen is oo circumference of second orbit of He would be. (1) 1.06 Å (2) 2.12 Å (2028 (46.668

Solution