(4) (RT)-12 (3) (RT)12 orium moles ...
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(4) (RT)-12 (3) (RT)12 orium moles of B and c 9. For the reaction A + 3B = 2C + D, initial mole of A is twice that of B. If at equilibrium mau A 13B 2040 are equal, then percent of B reacted is moler B (2) 20% 0 0 0 (1) 10% ETA B (4) 60% (3) 40% raban ann (og-3x) 2x x

NEET/Medical Exams
Chemistry
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( A+3 B Longrightarrow 2 C+D ) intialmes 2 ( u ) in [ begin{array}{c} 2 x-y quad x-3 y text { here }[0]=[c] therefore quad x-3 y=2 y x=5 y end{array} ] y. ( 91 mathrm{B} ) reack ( mathrm{d} Rightarrow frac{3 mathrm{d}}{mathrm{x}} ) xine [ Rightarrow quad 3left(frac{1}{5}right) times 100=60 % ]
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