Question

Часол a +1, 3+1 50 B3 Leta , ß are roots of 3x2 + x + 5 = 0, then find q. equation with roots as

JEE/Engineering Exams

Maths

Solution

4.0 (1 ratings)

( therefore quad 3(3 y+1)^{2}+(3 y+1)(y-1)+5=0 ) Apply ( y=frac{2 x+1}{2 x-3} ) componondo ( d x ) dividando [ begin{array}{l} frac{y+z}{y-1}=frac{4 x}{4} x=3 y+1 end{array} ] replere Now put ( alpha ) in eq