Question

( begin{aligned} & log _{e} 4+log _{4} e & log _{a} b=frac{1}{log _{b} a} =& 2 log _{e} 2+frac{1}{2 log _{e} 2} =& 2 times 0.693+frac{1}{2 times 0.693}=& log _{e^{2}}=0.693 & text { answer } ) text { grieater than } 2 end{aligned} )

# (A) A,D,C,D loge 4+ loge is (A) negative (B) equal to 2 i lon 7-? Innoy + loanz + logox = 2 & logaz + log 16x + log (C) >2

Solution