- A sound wave of wavelength 40 cm ...
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- A sound wave of wavelength 40 cm travels in air. If the difference between the maximum and minimum pressures at a given point is 1 x 10 9 Nm? What will be the amplitude of vibration of the particle of the medium, the bulk modulus of air is 1.4 x 10-10 Nm? a. 4.4x10-10 m b. 3.3x10-10 m c. 11x10-10 m d. 2.2 x 10-10 m

JEE/Engineering Exams
Physics
Solution
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Thilk modulus ob ain is ( 1.4 times 10^{5} mathrm{N} / mathrm{m}^{2} ) ( P_{0}=frac{|x| 0^{-3}}{2}=10^{-3} / 2 ) difpl amplitude (so) ( S_{0}=P_{0} / B_{k}=P_{0} lambda / 2 pi B ) ( Rightarrow S_{0}=frac{frac{10^{-3}}{2} times 40 times 10^{-2}}{2 times pi times 1.4 times 10^{5}} ) ( Rightarrow mid S_{0}=3.3 ) Á
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