Question

( a_{1}+a_{n}+a_{7}+a_{10}+a_{13}+a_{16}=114 )
2) ( a+a+3 d+a+6 d+a+9 d+a+12 d )
( +a+15 d=114 )
( Rightarrow 6 a+45 d=114 )
( Rightarrow-a+9 d=pm 9 ) j ( 2 a+15 d=38 )
( therefore a_{1}+9_{6}+a_{4}+a_{16} )
( =a+a+5 d+a+10 d+a+15 phi )
( =4 a+30 d )
( begin{aligned} operatorname{sen}^{20} sin ^{2} x &=2(2 a+15 d) &=76 text { tuse } end{aligned} )
( f(2 ) give sating tanu

# +as is equal Ifa, a, az, .........., a are in A.P. and a, +a+a, + .......... +0,6 = 114, then a, +as+a TO (4) 38 (1) 64 (2)98 (3) 76

Solution