(BT:2 A particle travels 10m in fir...
Question  # (BT:2 A particle travels 10m in first 5 sec and 10m in next 3 sec. Assuming constant acceleration what is the distance travelled in next 2 sec. (A) 8.3 m (B) 9.3 m (C) 10.3 m (D) None of above com mund It exneriences a constant resistance force which can

JEE/Engineering Exams
Physics
Solution 160 4.0 (1 ratings)  G in ( 1^{text {st }} ) s sec trauelled cerstaure ( =10 mathrm{m} ) " 1.co ( therefore quad s_{1}=u++frac{1}{2} a t^{2} ) ( S_{f}=4(5)+frac{1}{2} a(5)^{2}=10 quad+(7 ) ( S_{8}=4(B)+frac{1}{2} 9(B)^{2}=20 ) ( S_{10}=4(10)+frac{1}{2} a(10)^{2}=? ) From 0 ell [ begin{array}{l}24+59=4 24+89=50end{array} ] : ( quad frac{3 q}{a^{2} P_{3}} quad 2 u=4-5 / 3 ) ( =7 / 6 ) ( therefore quad S_{10}=frac{7}{6} timesleft[0+frac{1}{2} times frac{1}{3} times(10)^{L}right. ) ( Rightarrow quad frac{35}{3}+frac{50}{3} ) a) ( frac{85}{3} ) ( S x_{0}-20=A x ) ( frac{85}{3}-20=frac{25}{3}=8 cdot 3 ) Quick and Stepwise Solutions Just click and Send OVER 20 LAKH QUESTIONS ANSWERED Download App for Free