Question

G in ( 1^{text {st }} ) s sec trauelled cerstaure ( =10 mathrm{m} ) "
1.co
( therefore quad s_{1}=u++frac{1}{2} a t^{2} )
( S_{f}=4(5)+frac{1}{2} a(5)^{2}=10 quad+(7 )
( S_{8}=4(B)+frac{1}{2} 9(B)^{2}=20 )
( S_{10}=4(10)+frac{1}{2} a(10)^{2}=? )
From 0 ell
[
begin{array}{l}24+59=4 24+89=50end{array}
]
: ( quad frac{3 q}{a^{2} P_{3}} quad 2 u=4-5 / 3 )
( =7 / 6 )
( therefore quad S_{10}=frac{7}{6} timesleft[0+frac{1}{2} times frac{1}{3} times(10)^{L}right. )
( Rightarrow quad frac{35}{3}+frac{50}{3} )
a) ( frac{85}{3} )
( S x_{0}-20=A x )
( frac{85}{3}-20=frac{25}{3}=8 cdot 3 )

# (BT:2 A particle travels 10m in first 5 sec and 10m in next 3 sec. Assuming constant acceleration what is the distance travelled in next 2 sec. (A) 8.3 m (B) 9.3 m (C) 10.3 m (D) None of above com mund It exneriences a constant resistance force which can

Solution