(C) b2 - 4ac If the roots of the eq...
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(C) b2 - 4ac If the roots of the equation are equal in magnitude but opposite in sign, then their product is (A) (03 +82) (B) 72 (Q2 +82) (C) Lab (D) 2 ab cu 10

JEE/Engineering Exams
Maths
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( frac{1}{n+a}+frac{1}{n+b}=frac{1}{c} cdot(1, p+n o+n) ) ( Rightarrow frac{n+a+n+b}{(n+a)(n+b)}=frac{1}{c} ) ( (2 x+a+b) e=frac{a}{n}+b n+a n+a b ) ( Rightarrow quad 2 x+a e+b c=n+b c+a b=0 ) 2) ( x^{2}+a n+b n- ) ( 2(a b-a i-b c)=0 ) ( Rightarrow quad x^{2}+(a+b-2 c) n+ ) ( u_{0}-a-b c ) ( 2 alpha=frac{(-a-b+2 c)}{1} ) ( alpha cdot beta= ) ( alpha^{2}=left(a_{b}-a x-b cright) ) ( r ) A) ( arctan left(2(-a-b)^{2}=4right. ) a ( 20 mathrm{b} ) 4) 6 12 ( a^{2}+b^{2}+2 a ) ( Rightarrowleft(2 x^{3}(-5)^{2}+5^{4}right)^{4}-4(2+5) ) 2) ( 4 e^{2}+97 b^{2}+2 a b )
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