. If p and q are chosen randomly fr...
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. If p and q are chosen randomly from the set {1, 2, 3, 4, 5, 6, 7, 8, 9, 10), with replacement, then the probability that the roots of the equation x + px + 9 = 0 are real is (a) 0.62 (b) 0.65 (c) 0.70 (d) N.O.T. Aldanotturnovo temo hirthdavi

JEE/Engineering Exams
Maths
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( x^{2}+p x+q=0 ) For real noots ( p^{2} geqslant 4 q ) possible ralues ( 1 p=2 Rightarrow q=1 ) ( 2 quad p=3 Rightarrow q=1,2 ) ( 4 quad p=4 Rightarrow q=1,2,3,4 ) ( 6-4 Rightarrow q=1,2,3,4 ) ( 9=5 Rightarrow q=1,2,3,4,5,6 ) ( P=6 Rightarrow q=1,2,3,4,5,6,7,8,9 ) ( 10 quad p=7 Rightarrow q=1,2,3,4,5,6,7,8, ) ( 10 quad p=7 Rightarrow q=1,2,3,4,5,6,7,8,9,10 ) ( 10, p=8 Rightarrow q=1,2,3,4,5,6,7,8,29,10 ) 10 ( p=9 Rightarrow q=1,2,3,4,5,6,7,8,9,10 ) ( f mid 0 quad p=10 Rightarrow q=1,2,3,4,5,6,7,8,9,10 ) Total possible ( =100 quad{10 times 10} ) Probablity ( =frac{62}{100} ) dns: ( rightarrow )
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