(iv) x + x4 + x2 +1, when x = = 1+i...
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(iv) x + x4 + x2 +1, when x = = 1+i

JEE/Engineering Exams
Maths
Solution
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x6+x4+x2+1=x4(x2+1)+(x2+1)=(x4+1)(x2+1) =1+i44+11+i22+1 =1+4i+6i2+4i3+i4+441+i22i+22 =(5+4i-6-4i+1)4(1-1+2i+22)=0

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