Question

line to distance from point
( = ) radius
( frac{3 x+4 y-5}{sqrt{9+16}}=sqrt{2,1} )
( frac{6+4-5}{5}=r )
( frac{sqrt{8}=1}{(x-2)^{2}+(4+1)^{2}}=(1)^{2} )
( x^{2}+y^{2}-4 x-2 y+4=02 )

# - The equation to the circle with centre (2, 1) and [2006] touching the line 3x + 4y = 5 is er a. x2 + y2 - 4x - 2y + 5 = 0 b. x² + y2 - 4x - 2v-5-0 arby, ter a 475 C. x2 + y2 - 4x - 2y + 4 = 0 d. x² + y2 - 4x – 2y -4 = 0 B a 302) 44610-5

Solution