- The equation to the circle with c...
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- The equation to the circle with centre (2, 1) and [2006] touching the line 3x + 4y = 5 is er a. x2 + y2 - 4x - 2y + 5 = 0 b. x² + y2 - 4x - 2v-5-0 arby, ter a 475 C. x2 + y2 - 4x - 2y + 4 = 0 d. x² + y2 - 4x – 2y -4 = 0 B a 302) 44610-5

JEE/Engineering Exams
Maths
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line to distance from point ( = ) radius ( frac{3 x+4 y-5}{sqrt{9+16}}=sqrt{2,1} ) ( frac{6+4-5}{5}=r ) ( frac{sqrt{8}=1}{(x-2)^{2}+(4+1)^{2}}=(1)^{2} ) ( x^{2}+y^{2}-4 x-2 y+4=02 )
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