Question

( begin{aligned} A+C+quad A+B+C+D &=22500 rightarrow 0 (A+B) &=frac{3}{2} times(B+D) end{aligned} )

# (u) 4000 (c) 4500 22. A sum of * 22,500 is distributed among A, B, C and D such that (A+C) get part of (B+D), B gets t of D and A gets thrice of C then the money got by each of them is: /z. 2200 A,

Solution