0.6 In the arrangement shown in fig...
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0.6 In the arrangement shown in figure, coefficient of friction between the two blocks is u= friction (in N) acting between the two blocks is: The force of 151 2kg F=2N F2 = 20 4kg Smooth

JEE/Engineering Exams
Physics
Solution
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( begin{aligned} mathbb{A}_{text {het }} text { for consination } &=frac{20-2}{6} &=3 mathrm{m} / mathrm{s} end{aligned} )
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