0.88 If an angle A of a AABC satisf...
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0.88 If an angle A of a AABC satisfies 5 cos A + 3 = 0, then the roots of the quadratic equation, 9x2 + 27x + 20 = 0 are - (JEE-Main Online-2018] (A) sin A, sec A (B) sec A, tan A (C) tan A, cos A (D) sec A, cot A

JEE/Engineering Exams
Maths
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( x+a+=-frac{3}{5} ) ( x+n=frac{4}{-3} ) ( 9 x^{2}+27 x+20=0 ) 3) ( 6 x^{2}+2 cdot 3 x cdot frac{27}{8}^{9} d x+frac{81}{4}+20-frac{81}{4}=0 ) ( 1left(3 n+frac{9}{2}right)^{2}= ) 2) ( left(3 n+frac{9}{2}right)^{2}=frac{1}{4} )
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