Question

Date No of moles in oiditg of ( N_{1} f_{3} )
( =frac{0.017}{17}=0.06 )
mole of ( N H_{3}=6.023 times 10^{23} )
begin{tabular}{r}
( 0.001 mathrm{malos} quad frac{1}{N H_{3}=6.023 times 10^{20} mathrm{molecule}} )
hline
end{tabular}
I molecule of ( N H_{3}=10 ) pratons ( begin{aligned}left(6.023 times 10^{20}right) text { molecule } &=10 times 6.023 times 10^{20} 0,143 &=6.023 times 10^{21} end{aligned} )

# 0. Find out the no of protensers on Img of

Solution