Question

( f(x)=2 x^{2}+p x+4 )
( p(2)=8+2 p+4=0 )
( p(x)=-12 Rightarrow p=-6 )
( therefore quad 2 x^{2}-16 x+4=0 )
( 2 x^{2}-4 x-2 x+4=0 )
( (x-2)(2 x-2)=0 )
Other ( 20 x 0=1 )
value of ( p=-6 )

# 019: If one zero of polynomial 2x2 + px + 4 is 2, find the other zero. Also find p.

Solution