Question

SOLUTION We have
[
begin{array}{l}
Rightarrowleft[begin{array}{cc}
2 & 3 & 4
5 & x
end{array}right]+left[begin{array}{cc}
1 & y
0 & 1
end{array}right]=left[begin{array}{cc}
7 & 0
10 & 5
end{array}right]
Rightarrowleft[begin{array}{cc}
6 & 8
10 & 2 x
end{array}right]+left[begin{array}{cc}
1 & y
0 & 1
end{array}right]=left[begin{array}{cc}
7 & 0
10 & 5
end{array}right]
Rightarrow quad 2 x+1=5 text { and } 8+y=0
left.begin{array}{c}
6+1
10+0 & 2 x+1
end{array}right]
Rightarrow quad 2 x+left[begin{array}{cc}
7 & 0
10 & 5
end{array}right]
end{array}
]
[comparing the corresponding elements
( Rightarrow quad x=2 ) and ( y=-8 )
[
Rightarrow quad(x-y)=2-(-8)=10
]

# 07 EXAMPLE 4 2 + 5 find (x - y).

Solution