Question

( I cos theta=left[begin{array}{l}cos theta 0 0 & cos thetaend{array}right] )
( J sin theta=left[begin{array}{cc}0 & sin theta -sin & 0end{array}right] )
(1) ( +mathbb{C} )
Icono ( sin theta=left[begin{array}{cc}cos theta & sin theta -sin theta & cos cend{array}right]=B )
( =>(A) ) thes prive ting

# 1 010 और B = | a = 0 1 (A) Icos0+ Jsine coso sino Et al B= 1-10 -sino cos (B) Icoso-Jsino (C) Isino+Jcoso IcosO+Jsino

Solution