Question

( f_{n}=frac{(n+2)(n+3)}{4} )
o) ( frac{1}{t n}=frac{4}{(n+2)(n+3)} )

# 1+1 8. Ift = (n + 2)(n+3) for n = 12,3,..., then +1+1+...+ 1 equals 4 ty tz 2003 la 4006 3006 (b) 4003 3007 4006 3008 4006 3009

Solution

Instasolv

Solution