Question

( rightarrow operatorname{given} n=4.07 times 10^{-8} mathrm{cm} )
( d=10 cdot 5 mathrm{g} / mathrm{cm}^{3} )
( z=4 )
( therefore ) We trow ( r quad D=frac{2 m}{a^{3} N A} )
( y )
F) ( frac{4 x}{4} frac{10 cdot 5 times 164 times 10^{-24} times 6 times 10^{23}}{4} )
( M quad ) 白 ( 1000 times 10^{-1} mathrm{r} cdot frac{100 cdot 8 mathrm{gm}}{2} )

# 1.11 Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10- cm and density is 10.5 g cm. calculate the atomic mass of silver.

Solution