1.11 Silver crystallises in fcc lat...
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1.11 Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10- cm and density is 10.5 g cm. calculate the atomic mass of silver.

NEET/Medical Exams
Chemistry
Solution
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( rightarrow operatorname{given} n=4.07 times 10^{-8} mathrm{cm} ) ( d=10 cdot 5 mathrm{g} / mathrm{cm}^{3} ) ( z=4 ) ( therefore ) We trow ( r quad D=frac{2 m}{a^{3} N A} ) ( y ) F) ( frac{4 x}{4} frac{10 cdot 5 times 164 times 10^{-24} times 6 times 10^{23}}{4} ) ( M quad ) 白 ( 1000 times 10^{-1} mathrm{r} cdot frac{100 cdot 8 mathrm{gm}}{2} )
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