1. 50, 000 Ms. mole of mixture of N...
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1. 50, 000 Ms. mole of mixture of Ng. NO, and N, O, has a mean molar mass of 55.4 x on which all the N, O, may be dissociated into NO, the mean molar mass tends What is the mole ratio of NNO, and N, O, in the original mixture? e molar mass of the protein ins (MA2 (D) 12.00.000 On heating to a temperature. ass tends to a lower value of 39.6 g. (A) 5:1:4 A protein, isolated from a bovine © 1:1:1 (D) 1:5 : 4

JEE/Engineering Exams
Chemistry
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Let the number of moles of ( mathrm{N}_{2} ) be ( mathrm{X} ), the number of moles of ( mathrm{NO}_{2} ) be ( mathrm{y} ). and number of moles of ( mathrm{N}_{2} mathrm{O}_{4} ) be ( mathrm{Z} ). Total moles ( =1 ) So ( x+y+z=1 ) Equation 1 Molar mass of ( mathrm{N}_{2}=28 ) Molar mass of ( mathrm{NO}_{2}=46 ) Molar mass of ( mathrm{N}_{2} mathrm{O}_{4}=92 ) Mean average of the molar mass ( =frac{28 x+46 y+92 z}{x+y+z}=55.6 ) Using the relation ( x+y+z=1 ) ( 28 x+46 y+92 z=55.6 ) Equation 2 moles of ( mathrm{NO}_{2} ) formed from ( mathrm{N}_{2} mathrm{O}_{4}=2 mathrm{z} ) Hence after reaction, ( mathrm{NO}_{2}=mathrm{y}+2 mathrm{z} ) Now mean average of the molar mass after reaction ( =frac{28 x+46 y+92 z}{x+y+2 z}=39.6 ) Equation 3 Solving the three equations We get ( x=0.5 ) ( y=0.1 ) ( z=0.4 ) Thus the ratio becomes ( x: v: z=0.5: 0.1: 0.4 )
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