1) 67000 2) 34000 317000 4) 20000 3...
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1) 67000 2) 34000 317000 4) 20000 3. X and Y are two different elements having their atomic masses in 1: 2 ratio. The compound formed by the combination of X and Y contains 50% of X by weight. The empirical formula of the compound is 1) X,Y 2) XY, 3) XY4) X Y

JEE/Engineering Exams
Chemistry
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Assume total mass ( =100 mathrm{g} ) percentage = gram per loogramg ( therefore ) we have ( 50 mathrm{g} ) of ( x ) having atomic. mass and ( 50 mathrm{g} ) of ( y ) having atomic mriss ( b ) [ (b=2 a) ] given ratio No. ( U_{5} ) moles of ( x=frac{50}{a} ) No of motes us ( y=frac{50}{29}=frac{25}{a} ) divide by srarllest to give sirnplest whole number reatio bur ( x ) gives [ frac{frac{50}{a}}{frac{2 s}{a}}=frac{25}{frac{frac{25}{a}}{frac{25}{a}}}=1=y ] Therefore, emperifal formula is ( x_{2} y ). OPtion (1) is correet.
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