Question

( frac{1}{alpha^{3}}+frac{1}{beta^{3}}=frac{alpha^{3}+beta^{3}}{(alpha beta)^{3}}=frac{frac{3 a b c-b^{3}}{a^{3}}}{left(frac{c}{a}right)^{3}} )
( Rightarrow quad frac{1}{alpha^{3}}+frac{1}{beta^{3}}=frac{3 a b c-b^{3}}{c^{3}} )

# 1. and p are the zeroes of the quadratic polynomial f(x)= ax + bx+c then evaluate --- Q? 23

Solution