Question
? Comg compendo- bicendo law
[
begin{array}{l}
frac{a}{b}-frac{c}{d}
Rightarrow frac{a+b}{a-b}=frac{c+d}{c-d}
end{array}
]
( frac{operatorname{Th} mu}{sin A sin B}=frac{3}{1} )
[
Rightarrow frac{cos A cos B+sin A sin B}{cos A cos B-sin A sin beta}=frac{3+1}{3-1}
]

1 cos A cos B 3 sin A sin B 1 cos A cos B + sin A sin B cos A cos B - sin A sin B 3+1 3-1 1
Solution
