1. f logM + Blogs N = 1 + logo.0085...
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1. f logM + Blogs N = 1 + logo.0085, then (1) M° = (2) N = (3) M3 =130 SI (4) N9 - 3

JEE/Engineering Exams
Maths
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( begin{array}{c}log _{3} M^{1 / 3}+log _{3} N^{3}=1+log _{(1-2)^{3}} Rightarrow log _{3}left(M^{1 / 3} cdot N^{3}right)=1+frac{1}{3} log _{5^{-1}} 5 = & 1-frac{1}{3} & =frac{1 / 3}{1} cdot N^{3}=3^{2 / 3}end{array} ) ( Rightarrow quad M, N^{y}=frac{9}{a} ) (2) Ans: ( x^{9}=frac{9}{4} )
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