Question

( R={2,4,6,8-cdots} quad[because d text { ivis ible by } 2] )
( s={3,6,9,12 ldots,} ) " divisible by 3 Besed none of the above
( R-S={2,4,8 cdots,} )
( R cup S={2,3,4,6,8,9 cdot cdot cdot} )
( operatorname{Rns}={6,12,18 cdot cdots} )
80 none of the above option

# 1. Let R & S be the sets defined as follows R={xel : x is divisible by 2}, S ={xel :x is divisible by 3) then Ni a (a) RUS = {2, 3, 4, 5, 6, ...} (b) ROS = 0 (c) R-S={2, 4, 5, 7, ... Let A = {xelt: r* - 13.x? +36=0} then d) none of these ?

Solution