1 mole of CO2 gas at 300 K is expan...
Question
Fullscreen

1 mole of CO2 gas at 300 K is expanded under reversible adiabatic condition such that its volume becomes 27 times. (a) What is the final temperature ? (b) What is work done ? Given y = 1.33 and Cy = 25.08 Jmol-'K-' for CO2.

JEE/Engineering Exams
Chemistry
Solution
118
Rating
4.0 (1 ratings)
Fullscreen
Qiven [ gamma=1.33 text { and } C_{1}=25.08 frac{mathrm{J}}{mathrm{mot}} mathrm{cor} mathrm{co}_{2} ] (a) Adiabate Condition [ begin{array}{l} frac{T_{2}}{T_{1}}=left(frac{V_{1}}{V_{2}}right)^{gamma-1} therefore quad T_{2}=(300 k)left[frac{1}{27}right]^{0.33}=100 mathrm{k} end{array} ] Sina TreT. ( (B) quad Delta E=q+omega ) ( q=0 quad ) bon adiabatic condition. ( begin{aligned} therefore quad omega &=-Delta E &=-C_{v}left(T_{2}-T_{1}right)=-25.08(100-300) &=5016 mathrm{F} end{aligned} )
Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free