Question

( begin{aligned} E &=frac{-d v}{d x} quad text { कᅮ } &=frac{-d}{d x}left(4 x^{2}right) &=-(8 x) &=-(8 times 1)=-8 mathrm{v} / mathrm{m} text { along } & text { -ve } x-text { axis } end{aligned} )

# 1. The electric potential V at any point o (x, y, z all in metres) in space is given by V = 4x2 V. The electric field at the point (1 m, 0,2 m) in V/m is (a) 8 along negative x-axis (b) 8 along positive x-axis (c) 16 along negative x-axis (d) 16 along positive z-axis nost (

Solution