1. The equation of the tangent to t...
Question
Fullscreen

1. The equation of the tangent to the conic x2 - y2 – 8x + 2y + 11 = 0 at (2, 1), is (a) x + 2 = 0 (b) 2x + 1 = 0 (C) x – 2 = 0 (d) x + y + 1 = 0

JEE/Engineering Exams
Maths
Solution
273
Rating
4.0 (1 ratings)
Fullscreen
( x^{2}-y^{2}-8 x+2 y+11=0 ) (2,1) tangent Slope of tongent at (2,1) is [ begin{array}{l} f^{prime}(2,1)=2 x+2=8 (x-4)^{2}-(y-1)^{2}=4 quad(y-1)^{2}=(x-4-2)(x-4+2) f(x)=y=1 pm sqrt{(x-6)(x-2)} f^{prime}(x)=pm frac{1(2 x-8)}{2 sqrt{(x-6)(x-2)}} frac{y^{prime}(2)}{x-2}=frac{1}{0} end{array} ] ( x=2 )
Quick and Stepwise Solutions Just click and Send Download App OVER 20 LAKH QUESTIONS ANSWERED Download App for Free