Question

( a, a+1, a+2 )
( 3 a+3(a+1+7 mid a+2)=124 )
( 3 a+5 a+7 a+5+14=124 )
( 15 a quad=105 )
( a quad=105115=7 )
( therefore quad ) ihe nos. an 7,8,9

# 1. Three consecutive integers are such that when they are taken in increasing order and multip! 3,5 and 7 respectively, they add up to 124. Find these numbers. number is

Solution