Question

1. What is the value of sin 34° cos 236º – sin 56° sin 124° , cos 28° cos 88° + cos 178° sin 208° (a) -2 (b) - 1

JEE/Engineering Exams

Maths

Solution

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( sin 3 y^{circ} cos 236-sin 56^{circ} sin 124 ) Cuere wers + cerlgro faty ( 208^{circ} ) fing ( 4 cos 236+cos 34 sin 236 ) ( cos 2 x^{0} cos 8 t^{0}+sin 8 x^{0} cdot sin 28^{circ} ) ( left(frac{cos (90+8 t)}{2-sin t 8}right. ) ( sin (180+theta) ) ( =-sin theta ) ( 6 sin (2 pi-theta) ) ( sin left(34^{circ}+236^{circ}right) ) ( cos left(28^{circ}-880right)=frac{sin 270^{circ}}{cos 60^{circ}} ) ( frac{-1}{4 x}=-2 )