Question

( lim _{x rightarrow 0} frac{log sin x}{frac{1}{x}}=frac{2}{x}+operatorname{sen} x )
ine L- - buepi to
( =frac{1+1}{n+0} frac{1}{sin x} cdot frac{cos x}{frac{-1}{x^{2}}} )
( =frac{L t}{x rightarrow 0} frac{-x^{2}}{tan x}=frac{4 t}{x+0}-frac{x cdot y^{1}-1}{tan x}=0 frac{(b)}{x+2 y} )

# 1 x log sinx is equal to (a) oo (b) Zero (d) Cannot be determined (C)1

Solution