Question

Not the comnon soot be ( x ).
[
begin{array}{l}
therefore quad alpha^{2}+b alpha+a=0 quad ldots(i)
quad a text { as } quad alpha^{2}+a alpha+b=0
end{array}
]
( (i)-[i 1) )
[
begin{array}{c}
(b-a) alpha=(b-a)
alpha=1
end{array}
]
( : quad begin{array}{r}f+b+a=0 a+b=-1end{array} )

# 10. If the equations x2 + ax + b = 0 and x2 + bx +a = 0 (a + b) have a common root then a+b= 1)-1 2003)1 42

Solution